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0.1688 g when analysed by the Dumas method yield 31.7 mL of moist nitrogen measured at 14^(@)C and 758 mm mercury pressure. Determine the % of N in the substance (Aqueous tension at 14^(@)C =12 mm of Hg).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Weight of Organic compound =0.168 g <br/> `"Volume of moist nitrogen" (V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))=31.7 ml=31.7 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) L` <br/> `"Temperature" (T_(1)) = 14^(@)C = 14 + 273 = 287 K` <br/> Pressure of Moist nitrogen (P) =758 mm Hg <br/> Aqueous tension at `14^(@)C` = 12 mm of Hg <br/> `:.` Pressure of <a href="https://interviewquestions.tuteehub.com/tag/dry-960094" style="font-weight:bold;" target="_blank" title="Click to know more about DRY">DRY</a> nitrogen=(`P-P^(1)`)=758-12=746 mm of Hg <br/>`(P_(1)V_(1))/(T_(1))=(P_(0)V_(0))/(T_(0))` <br/> `V_(0)=(746 xx 31.7 xx 10^(-3))/(287) xx (273)/(<a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a>)` <br/> `V_(0)=29.8 xx 10^(-3) L` <br/> `"Percentage of nitrogen"=((28)/(22.4) xx (V_(0))/(W)) xx 100` <br/> `=(28)/(22.4) xx (29.58 xx 10^(-3))/(0.1688) xx 100=21.90%`</body></html>


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