0.18g of a divalent metal was completely dissolved in 250 cc of acid s

1.	0.18g of a divalent metal was completely dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.
Answer» Answer: Explanation: SOLUTION of H2SO4 containing 4.9 g of H2SO4 PER litre. 50 CC of residual ACID solution were found to require 20 CC of N/10 alkali for complete neutralization. Calculate the equivalent weight of the metal0.18g of a divalent metal was COMPLETELY dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.

0.18g of a divalent metal was completely dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.

Answer»

Answer:

Explanation:

SOLUTION of H2SO4 containing 4.9 g of H2SO4 PER litre. 50 CC of

residual ACID solution were found to require 20 CC of N/10

alkali for complete neutralization. Calculate the equivalent

weight of the metal0.18g of a divalent metal was COMPLETELY dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.

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0.18g of a divalent metal was completely dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.​

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0.18g of a divalent metal was completely dissolved in 250 cc of acid solution containing 4.9 g H2SO4 per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. Calculate the atomic weight of metal.