`0.1914 g` of an organic acid is dissolved in about `20 mL` of water. `25 mL` of `0.12 N NaOH` is required for complete neutralization of the acid solution. The equivalent mass of the acid isA. `65.0`B. `64.0`C. `62.5`D. `63.8`

`0.1914 g` of an organic acid is dissolved in about `20 mL` of water.

1.	`0.1914 g` of an organic acid is dissolved in about `20 mL` of water. `25 mL` of `0.12 N NaOH` is required for complete neutralization of the acid solution. The equivalent mass of the acid isA. `65.0`B. `64.0`C. `62.5`D. `63.8`
Answer» Correct Answer - D According to the law of equivalence, `("Milliequival ents")_(NaOH) = ("Milliequi valents")_(o .acid)` `= (0.12)(25) = 3` `:.` Equivalents of organic acid `= (3)/(1000)` This implies that `3 xx 10^(-3)` equivalents of acid weigh `0.1914 g`. Thus, `1` equivalent of acid will weigh `(0.1914 g)/(3 xx 10^(-3) eq) = 63.8 g eq^(-1)` Hence, the equivalent mass of acid is `63.8 u`.

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`0.1914 g` of an organic acid is dissolved in about `20 mL` of water. `25 mL` of `0.12 N NaOH` is required for complete neutralization of the acid solution. The equivalent mass of the acid isA. `65.0`B. `64.0`C. `62.5`D. `63.8`

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