0.1g of carbon dioxide occupies a volume of 320cc at certain conditions. Under similar conditions 0.2g of 3 dioxide of element 'X' occupies 440cc. Calculate the atomic weight of 'X'.

0.1g of carbon dioxide occupies a volume of 320cc at certain condition

1.	0.1g of carbon dioxide occupies a volume of 320cc at certain conditions. Under similar conditions 0.2g of 3 dioxide of element 'X' occupies 440cc. Calculate the atomic weight of 'X'.
Answer» Solution :Applying Avogadro.slaw,` (n_(1))/(n_(2)) = (V_(1))/(V_(2))` But number of moles ` =n = w//M` `(V_(1))/(V_(2)) = (w_(1)M_(2))/(w_(2)M_(1))` Molecular weight of dioxide of X ` = M_(2) = (V_(1))/(V_(2)) XX (w_(2)m_(1))/(w_(1)) = (320)/(440) xx (0.2)/(0.1) xx 44 = 64` Molecular weight of `XO_(2) = 64` Therefore, ATOMIC weight of X = 32