0.1g of carbon dioxide occupies a volume of 320cc at certain conditions. Under similar conditions 0.2g of 3 dioxide of element 'X' occupies 440cc. Calculate the atomic weight of 'X'.

0.1g of carbon dioxide occupies a volume of 320cc at certain condition

1.	0.1g of carbon dioxide occupies a volume of 320cc at certain conditions. Under similar conditions 0.2g of 3 dioxide of element 'X' occupies 440cc. Calculate the atomic weight of 'X'.
Answer» <html><body><p></p>Solution :Applying Avogadro.slaw,` (n_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/(n_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) = (V_(1))/(V_(2))`<br/> But number of moles ` =n = w//M` <br/> `(V_(1))/(V_(2)) = (w_(1)M_(2))/(w_(2)M_(1))` <br/> Molecular weight of dioxide of X ` = M_(2) = (V_(1))/(V_(2)) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (w_(2)m_(1))/(w_(1)) = (320)/(440) xx (0.2)/(0.1) xx <a href="https://interviewquestions.tuteehub.com/tag/44-316683" style="font-weight:bold;" target="_blank" title="Click to know more about 44">44</a> = 64` <br/> Molecular weight of `XO_(2) = 64` <br/> Therefore, <a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> weight of X = 32</body></html>