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0.2 g off an organic compound contains C, H and O. On combustion, it yields 0.15 g CO_(2) and 0.12" g "H_(2)O. The percentage of C, H and O respectively is |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>=15%,<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>=20%,O=65%`<br/>`C=10%,H=8.2%,O=81.8%`<br/>`C=12.2%,H=8.8%,O=79%`<br/>`C=20%,H=6.66%,O=73.34%`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :% of `C=(12)/(44)xx(0.15)/(0.2)xx100=20%` <br/> % of `H=(2)/(18)xx(0.12)/(0.2)xx100=6.66%` <br/> % of `O=100-(20+6.66)=73.34%`</body></html> | |