1.

0.2 g off an organic compound contains C, H and O. On combustion, it yields 0.15 g CO_(2) and 0.12" g "H_(2)O. The percentage of C, H and O respectively is

Answer»

`C=15%,H=20%,O=65%`
`C=10%,H=8.2%,O=81.8%`
`C=12.2%,H=8.8%,O=79%`
`C=20%,H=6.66%,O=73.34%`

SOLUTION :% of `C=(12)/(44)xx(0.15)/(0.2)xx100=20%`
% of `H=(2)/(18)xx(0.12)/(0.2)xx100=6.66%`
% of `O=100-(20+6.66)=73.34%`


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