0.2 of an organic compound containing phosphorusgave 1.877 g of ammonium phosphomolybdate by usual analysis. Calculate the percentage of phosphorus in the organic compound.

0.2 of an organic compound containing phosphorusgave 1.877 g of ammoni

1.	0.2 of an organic compound containing phosphorusgave 1.877 g of ammonium phosphomolybdate by usual analysis. Calculate the percentage of phosphorus in the organic compound.
Answer» <P> SOLUTION :`UNDERSET(1877g)((NH_(3))_(3)PO_(4). 12MoO_(3)) -= underset(31g)(P)` `:. % P = (31)/(1877) xx (1.877)/(0.2) = 15.5`