0.2 of an organic compound containing phosphorusgave 1.877 g of ammonium phosphomolybdate by usual analysis. Calculate the percentage of phosphorus in the organic compound.

0.2 of an organic compound containing phosphorusgave 1.877 g of ammoni

1.	0.2 of an organic compound containing phosphorusgave 1.877 g of ammonium phosphomolybdate by usual analysis. Calculate the percentage of phosphorus in the organic compound.
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(1877g)((NH_(3))_(3)PO_(4). 12MoO_(3)) -= underset(31g)(P)` <br/> `:. % P = (<a href="https://interviewquestions.tuteehub.com/tag/31-306830" style="font-weight:bold;" target="_blank" title="Click to know more about 31">31</a>)/(1877) xx (1.877)/(0.2) = 15.5`</body></html>