0.2004 g of glucose gave on combustion 0.2940 g of CO_(2) and 0.1202 g of H_(2)O. Find the percentage composition.

0.2004 g of glucose gave on combustion 0.2940 g of CO_(2) and 0.1202 g

1.	0.2004 g of glucose gave on combustion 0.2940 g of CO_(2) and 0.1202 g of H_(2)O. Find the percentage composition.
Answer» Solution :Weight of ORGANIC compound = 0.2004 g Weight of carbon dioxide = 0.2940 g Weight of water = 0.1202 g Percentage of carbon 44 g of CO2 contains, carbon = 12 g `"0.2940 g of "CO_(2)" contains, carbon"=(12xx0.2940)/(44)xx(100)/(0.2004)=40.01` Percentage of HYDROGEN 18 g of `H_(2)O` contains, hydrogen = 2 g 0.1202 of `H_(2)O` contains, hydrogen `=(2xx0.1202)/(18)` Percentage of hydrogen `=(2xx0.1202)/(18)xx(100)/(0.2004)=6.66` Percentage of OXYGEN is therefore by difference, `=[100-(40.01+6.66)]=53.33`