0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen measured at 288 K and 732.7 mm pressure. Calculate the percentage of nitrogen in the compound (Aqueous tension at 288 K is 12.7 mm)

0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen mea

1.	0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen measured at 288 K and 732.7 mm pressure. Calculate the percentage of nitrogen in the compound (Aqueous tension at 288 K is 12.7 mm)
Answer» Solution :Step I. Volume of `N_(2)` at N.T.P. `{:("Experimental Conditions","N.T.P. Conditions"),(V_(1)=30.4 cm^(3),V_(2)=?),(P_(1)=732.7-12.7=720 mm,P_(2)=760 mm),(T_(1)=288 K,T_(2)=273 K):}` `(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)` or `V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=((720mm)XX(30.4 cm^(3))xx(273 K))/((288 K)xx(760 mm))=27.3 cm^(3)` Step II. Percentage of nitrogen `=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of COMPOUND")xx100=28/22400xx27.3/0.2046xx100=16.68 %`