0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen measured at 288 K and 732.7 mm pressure. Calculate the percentage of nitrogen in the compound (Aqueous tension at 288 K is 12.7 mm)

0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen mea

1.	0.2046 g of an organic compound gave 30.4 cm^(3) of moist nitrogen measured at 288 K and 732.7 mm pressure. Calculate the percentage of nitrogen in the compound (Aqueous tension at 288 K is 12.7 mm)
Answer» <html><body><p><br/></p>Solution :Step I. Volume of `N_(2)` at N.T.P. <br/> `{:("Experimental Conditions","N.T.P. Conditions"),(V_(1)=30.4 cm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>),V_(2)=?),(P_(1)=732.7-12.7=720 mm,P_(2)=<a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a> mm),(T_(1)=<a href="https://interviewquestions.tuteehub.com/tag/288-1834218" style="font-weight:bold;" target="_blank" title="Click to know more about 288">288</a> K,T_(2)=273 K):}` <br/> `(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)` or `V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=((720mm)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(30.4 cm^(3))xx(273 K))/((288 K)xx(760 mm))=27.3 cm^(3)` <br/> Step II. Percentage of nitrogen <br/> `=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a>")xx100=28/22400xx27.3/0.2046xx100=16.68 %`</body></html>