0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate chloride completely. If the specific heat of metal is 0.057 ca g^(-1), find the molecular formula of metal chloride?

0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate ch

1.	0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate chloride completely. If the specific heat of metal is 0.057 ca g^(-1), find the molecular formula of metal chloride?
Answer» ANSWER :`MCl_(3)`