0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate chloride completely. If the specific heat of metal is 0.057 ca g^(-1), find the molecular formula of metal chloride?

0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate ch

1.	0.22g of a metal chloride required 0.51g of AgNO_(3) to precipitate chloride completely. If the specific heat of metal is 0.057 ca g^(-1), find the molecular formula of metal chloride?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`MCl_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html>