0.2346 g of an organic compound containing C, H & 0, on combustion gives 0.2754 g of H_(2)0 and 0.4488 g CO_(2) . Calculate the % composition of C, H & 0 in the organic compound.

0.2346 g of an organic compound containing C, H & 0, on combustion giv

1.	0.2346 g of an organic compound containing C, H & 0, on combustion gives 0.2754 g of H_(2)0 and 0.4488 g CO_(2) . Calculate the % composition of C, H & 0 in the organic compound.
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of organic substance (<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>) = 0.2346 g <br/> Weight of water (x) = 0.2754 g<br/> Weight of `CO_(2)` (y) = 0.4488 g <br/> `"Percentage of <a href="https://interviewquestions.tuteehub.com/tag/carbon-16249" style="font-weight:bold;" target="_blank" title="Click to know more about CARBON">CARBON</a>" = (12)/(44) xx (y)/(w) xx <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> = (12)/(44) xx (0.4488)/(0.2346) xx 100 = 52.17%` <br/> `"Percentage of hydrogen" =(2)/(18) xx (x)/(w) xx 100=(2)/(18) xx (0.2754)/(0.2346) xx 100=13.04%` <br/> Percentage of oxygen =[100-(52.17+13.04)]=100-65.21=34.79%</body></html>