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0.24 g of an organic compound gave 0.287 g of silver chloride in the carius method. Calculate the percentage of chlorine in the compound. |
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Answer» Weight of organic compound = 0.24 g Weight of silver chloride = 0.287 g 143.5 g of AgCl contains = 35.5 g of Cl 0.287 g of AgCl contains = \(\frac{35.5}{143.5}\) x 0.287 g of Cl % of chlorine = \(\frac{35.5}{143.5}\) x \(\frac{0.287}{0.24}\) x 100 = 29.58% |
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