0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2)P_(2)0_(7) by the usual analysis. Calculate the percentage of phosphorous in the compound

0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2

1.	0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2)P_(2)0_(7) by the usual analysis. Calculate the percentage of phosphorous in the compound
Answer» <html><body><p></p>Solution :Weight of an <a href="https://interviewquestions.tuteehub.com/tag/organic-1138713" style="font-weight:bold;" target="_blank" title="Click to know more about ORGANIC">ORGANIC</a> compound = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>.24 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/> Weight of `Mg_(2)P_(2)0_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)`= 0.66 g <br/> 222 g of `Mg_(2)P_(2)0_(7)` contains= 62 g of P <br/> `"0.66 g contains"=(62)/(222) xx 0.66 "g of P"` <br/> `"<a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a> of P"=(62)/(222) xx (0.66)/(0.24) xx 100=76.80%`</body></html>