0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2)P_(2)0_(7) by the usual analysis. Calculate the percentage of phosphorous in the compound

0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2

1.	0.24 g of organic compound containing phosphorous gave 0.66 g of Mg_(2)P_(2)0_(7) by the usual analysis. Calculate the percentage of phosphorous in the compound
Answer» Solution :Weight of an ORGANIC compound = 0.24 G Weight of `Mg_(2)P_(2)0_(7)`= 0.66 g 222 g of `Mg_(2)P_(2)0_(7)` contains= 62 g of P `"0.66 g contains"=(62)/(222) xx 0.66 "g of P"` `"PERCENTAGE of P"=(62)/(222) xx (0.66)/(0.24) xx 100=76.80%`