0.24 g of organic compound containing phosphorous gave 0.66 g of Mg2P2 – InterviewSolution

InterviewSolution

1.

0.24 g of organic compound containing phosphorous gave 0.66 g of Mg2P2O7 by the usual analysis. Calculate the percentage of phosphorous in the compound.

Answer»

Weight of an organic compound = 0.24 g

Weight of Mg₂P₂O₇ = 0.66 g

222 g of Mg₂P₂O₇ contains = 62 g of P

0.66 g contains = \(\frac{62}{222}\) x 0.66 g of P

Percentage of P = \(\frac{62}{222}\) x \(\frac{0.66}{0.24}\) x 100 = 76.80%

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