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0.2475 g of an organic compound gave on combustion 0.4950 g of carbon dioxide and 0.2025 g of water. Calculate the percentage of carbon and hydrogen in it. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a>. of organic <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> `= 0.2475` g <br/> Wt. of `CO_2` produced `= 0.4950` g <br/> Wt. Of `H_2 O` produced `= 0.20 25` g <br/> Percentage of carbon `= (<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)/(44) xx ("Wt. Of" CO_2)/("Wt. <a href="https://interviewquestions.tuteehub.com/tag/ofcompound-2885260" style="font-weight:bold;" target="_blank" title="Click to know more about OFCOMPOUND">OFCOMPOUND</a>") xx 100` <br/> `= (12)/(44) xx (0.34950)/(0.2475) xx 100 = 54.54` <br/> Percentage of hydrogen `= (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(18) xx ("Wt. of" H_2 O )/("Wt. of compound") xx 100` <br/> `= (2)/(18) xx (0.2025)/(0.2475) xx 100 = 9.09`</body></html> | |