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0.2475g of an organic compound gave on combustion 0.4950 of `CO_(2)` and 0.2025g of `H_(2)O` calculate the % of C `&` H in it. |
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Answer» Wt of organic compound (w)=0.2475g Wt of `CO_(2)(b)=0.4950g` Wt. of `H_(2)O(a)=0.2025g` % of `C=((12)/(44)xxb)/(w)xx100` `=((12)/(44)xx0.4950)/(0.2475)xx100=54.54` % of `H=((2)/(18)xxa)/(w)xx100` `=((2)/(18)xx0.2025)/(0.2475)xx100=9.09` |
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