0.24g of a gas dissolves in 1 L of water at 1.5 atm pressure. Calculate the amount of dissolved gas when the pressure is raised to 6.0 atm at constant temperature.

0.24g of a gas dissolves in 1 L of water at 1.5 atm pressure. Calculat

1.	0.24g of a gas dissolves in 1 L of water at 1.5 atm pressure. Calculate the amount of dissolved gas when the pressure is raised to 6.0 atm at constant temperature.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`P _("solute") = K_(H)x _("solute in solution")` <br/> At pressure `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5` atm, `P_(1) = K_(H) x _(1)""…(1)` <br/> At pressure `<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.0` atm,` P _(2) = <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> _(H) x _(2)""…(2)` <br/> Dividing equation (1) by (2) <br/> We get `(p _(1))/( p _(2)) = (x _(1))/( x _(2))` <br/> `(1.5)/(6.0) = (0.24)/(x _(2))` <br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> `x _(2) = (0.24 xx 6. 0)/(1.5) =0.96 g //L`</body></html>