0.25 g of an organic compound gave 30 cm^(3) of moist dinitrogen at 288 K and 745 mm pressure. Calculate the percentage of nitrogen . (Aq tension of 288 K =12.7 mm)

0.25 g of an organic compound gave 30 cm^(3) of moist dinitrogen at 28

1.	0.25 g of an organic compound gave 30 cm^(3) of moist dinitrogen at 288 K and 745 mm pressure. Calculate the percentage of nitrogen . (Aq tension of 288 K =12.7 mm)
Answer» Solution :Mass of substance =0.25 g Volume of moist dinitrogen =`30cm^(3)` Temperature =288 K Pressure= `745-12.7 =732.3 mm` STEP I . To reduce the volume of `N_(2)` at S.T.P We KNOW, `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `P_(2),T_(2),V_(2)` refer to S.T.P conditions) `V_(2)=(P_(1)V_(1))/(T_(1))xx (T_(2))/(P_(2))==(732.3xx30xx273)/(288xx760) =27.4 cm^(3)` Step II: Calculation of percentage of NITROGEN `22400 cm^(3)` of dinitrogenat S.T.P weight =28 g `27.4 cm^(3) ` of dinitronge at S.T.P weight `(28xx274)/22400 =0.034 g ` Percentage of nitrogen in organic compound `=0.034/0.25 xx100=13.6`