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0.25 g of an organic compound gave 30 cm^(3) of moist dinitrogen at 288 K and 745 mm pressure. Calculate the percentage of nitrogen . (Aq tension of 288 K =12.7 mm)

Answer» <html><body><p></p>Solution :Mass of substance =0.25 g <br/> Volume of moist dinitrogen =`30cm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> Temperature =288 K <br/> Pressure= `745-12.7 =732.3 mm`<br/> <a href="https://interviewquestions.tuteehub.com/tag/step-25533" style="font-weight:bold;" target="_blank" title="Click to know more about STEP">STEP</a> I . To reduce the volume of `N_(2)` at S.T.P <br/> We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a>, `(P_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` <br/> `P_(2),T_(2),V_(2)` refer to S.T.P conditions)<br/> `V_(2)=(P_(1)V_(1))/(T_(1))xx (T_(2))/(P_(2))==(732.3xx30xx273)/(288xx760) =27.4 cm^(3)` <br/> Step II: Calculation of percentage of <a href="https://interviewquestions.tuteehub.com/tag/nitrogen-1118291" style="font-weight:bold;" target="_blank" title="Click to know more about NITROGEN">NITROGEN</a> <br/> `22400 cm^(3)` of dinitrogenat S.T.P weight =28 g <br/> `27.4 cm^(3) ` of dinitronge at S.T.P weight `(28xx274)/22400 =0.034 g ` <br/> Percentage of nitrogen in organic compound `=0.034/0.25 xx100=13.6`</body></html>


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