1.

0.25 gram of an organic compound containing chlorine treated with excess of AgNO3, which gives 0.4 gram of AgCl as precipate out in carius method, then % of chlorine in organic compound is [Report your answer to nearest integer]

Answer»

Correct answer is 40

Organic compound \(\xrightarrow{AgNO_ 3}\) AgCl

(Containing chlorine) 0.4 gram

0.25 gram

Mole of AgCl = (0.4/143.5)

WCl = (0.4/143.5) x 35.5

% of Cl = [0.4/143.5 x 35.5] x 100/0.25 = 39.58



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