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0.25 gram of an organic compound containing chlorine treated with excess of AgNO3, which gives 0.4 gram of AgCl as precipate out in carius method, then % of chlorine in organic compound is [Report your answer to nearest integer] |
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Answer» Correct answer is 40 Organic compound \(\xrightarrow{AgNO_ 3}\) AgCl (Containing chlorine) 0.4 gram 0.25 gram Mole of AgCl = (0.4/143.5) WCl = (0.4/143.5) x 35.5 % of Cl = [0.4/143.5 x 35.5] x 100/0.25 = 39.58 |
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