0.25 mol of an ideal monoatomic gas undergoes isothermal expansion from a volume of 2.0 dm3 to 10 dm3 at 27°c. Calculate the maximum work that can be obtained from this process.

0.25 mol of an ideal monoatomic gas undergoes isothermal expansion fro

1.	0.25 mol of an ideal monoatomic gas undergoes isothermal expansion from a volume of 2.0 dm3 to 10 dm3 at 27°c. Calculate the maximum work that can be obtained from this process.
Answer» Maximum work is done in isothermal process and is -1.002kJExplanation:Work= 2.303nRTlog() where V1 and V2 are initial and final volume respectively∴ W=2.303(0.25)(8.31)(300)LOG(2/10) =-(1436)log(5) =-1002.35J = -1.002kJHere negative sign INDICATES that work is done by the gas, i.e the gas expands isothermally.Hope this ANSWER is helpful, if so pls MARK as Brainliest :)