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`0.250g` of an element M, reacts with excess fluorine to produce `0.547g` of the hexafluoride `MF_(6)`. What is the elemejnt : `[Cr = 52, Mo = 96, S = 32, Te = 127.6]` .A. CrB. MOC. SD. Te |
Answer» Correct Answer - B `M + 6F rarr MF_(6)` Mole of M = Mole of `MF_(6)` `("wt")/("Mole wt") = ("wt")/("Mol wt")` `(.25)/(x) = (.547)/(x + 19 xx 6)` `28.5 + .25x = .547x` `28.5 = .297 x rArr x = 95.959` so element is `= Mo` . |
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