0.257g of organic substance was heated with conc. sulphuric acid and t

1.	0.257g of organic substance was heated with conc. sulphuric acid and then distilled with excess of strong alkali .the ammonia gas evolved was absorbed in 50ml of .1M HCl which required 23.2ml of c for neutralization at the end of the process. Determine the % of nitrogen in the compound?
Answer» Vol of 0 .1M HCl taken = 50ml Vol of .1MNaOH used for neutralization of unused acid=23.2ml Now, 23.2 ml of .1MNaOH =23.2ml of .1MHCl Vol of .1MHCl unused=23.2ml Vol of .1MHCl required for neutralization of NH₃ = 50-23.2=26.8ml 26.8ml of .1MHCl=26.8ml of .1M NH₃ 100ml of 1M NH₃ solution contain nitrogen=14g 26.8 ml of .1M NH₃ solution contain nitrogen = 1426.8/101000 Percentage of Nitrogen=1426.8100/101000.257 =14.6%

0.257g of organic substance was heated with conc. sulphuric acid and then distilled with excess of strong alkali .the ammonia gas evolved was absorbed in 50ml of .1M HCl which required 23.2ml of c for neutralization at the end of the process. Determine the % of nitrogen in the compound?

Answer»

Vol of 0 .1M HCl taken = 50ml

Vol of .1MNaOH used for neutralization of unused acid=23.2ml

Now,

23.2 ml of .1MNaOH =23.2ml of .1MHCl

Vol of .1MHCl unused=23.2ml

Vol of .1MHCl required for neutralization of NH₃ = 50-23.2=26.8ml

26.8ml of .1MHCl=26.8ml of .1M NH₃

100ml of 1M NH₃ solution contain nitrogen=14g

26.8 ml of .1M NH₃ solution contain nitrogen = 14*26.8/10*1000

Percentage of Nitrogen=14*26.8*100/10*1000*.257

=14.6%