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0.25g of an organic compound gave 30cm^(3) of moist dinitrogen at 288K and 745mm pressure. Calculate the percentage of nitrogen. (Aqueous tension at 288K = 12.7mm) |
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Answer» <P> SOLUTION :Mass of the substance = 0.25gVolume of moist dinitrogen = `30cm^(3)` Temperature = 288K Pressure `= 745- 12.7 = 732.3mm` Volume of dinitrogen at S.T.P `V_(2) = (P_(1)V_(1))/(T_(1)) xx (T_(2))/(P_(2)) = (732.3 xx 30 xx 273)/(288 xx 760) = 27.4 CM^(3)` `22400cm^(3)` of dinitrogen at STP weight = 28g `27.4 cm^(3)` of dinitrogen at STP weight `= (28 xx 27.4)/(22400)` = 0.034g Percentage of NITROGEN in organic compound `=(0.034)/(0.25) xx 100 = 13.6` |
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