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0.26 g of an organic compundgave 0.039 g of water and 0.245 g of CO_2 on combustion. Calculate the percentage of carbon and hydrogen. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of organic compound =0.26 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/>Weight of water =0.039 g <br/>Weight of `CO_2`= 0.245 g <br/> Percentage of hydrogen <br/> 18 g of watercontains 2 g of hydrogen <br/> 0.039 mg of water contains`-(2)/(18)xx(0039)/(0.26)`of H <br/> % of hydrogen `-(0.39)/(0.26)xx(2)/(18)xx100=1.66%` <br/> Percentage of csarbon <br/> 44 g of `CO_2` contains 12 g of <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <br/>0.245 g `CO_2` contains=`(12)/(44)xx(0.245)/(0.26)g` of C <br/> %of <a href="https://interviewquestions.tuteehub.com/tag/carbon-16249" style="font-weight:bold;" target="_blank" title="Click to know more about CARBON">CARBON</a> =`(12)/(44)xx(0.245)/(0.26)xx100=25.69%`</body></html> | |