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0.28 g of nitrogenous compound was subjected to Kjeldahl's process to produce 0.17 g of NH_(3) . The percentage of nitrogen in the organic compound is |
Answer» <html><body><p>5<br/>2<br/>50<br/>80</p>Solution :0.17 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> `NH_(3)` will <a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> `(14/17 xx0.17)` g of nitrogen , i.e., 0.14 g of nitrogen <br/> % Nitrogen =`("<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of nitrogen ")/("Mass of compound ")xx100=0.14/0.28xx100=50%`</body></html> | |