0.28 g of nitrogenous compound was subjected to Kjeldahl's process to produce 0.17 g of NH_(3) . The percentage of nitrogen in the organic compound is

0.28 g of nitrogenous compound was subjected to Kjeldahl's process to

1.	0.28 g of nitrogenous compound was subjected to Kjeldahl's process to produce 0.17 g of NH_(3) . The percentage of nitrogen in the organic compound is
Answer» 5 2 50 80 Solution :0.17 G `NH_(3)` will CONTAINS `(14/17 xx0.17)` g of nitrogen , i.e., 0.14 g of nitrogen % Nitrogen =`("MASS of nitrogen ")/("Mass of compound ")xx100=0.14/0.28xx100=50%`