0.2g of an organic compound on analysis give 0.147g of carbondioxide, 0.12 g of water and 74.6 c,c of nitrogen at S.T.P. Calculate the weight percentages of constituents.

0.2g of an organic compound on analysis give 0.147g of carbondioxide,

1.	0.2g of an organic compound on analysis give 0.147g of carbondioxide, 0.12 g of water and 74.6 c,c of nitrogen at S.T.P. Calculate the weight percentages of constituents.
Answer» <html><body><p></p>Solution :Weight of <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> = w = 0.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> h , volume of `N_(2)` at STP = `v_(2)` = 74.6 cc <br/> `%C = (w_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)xx12xx100)/(wxx44) = (0.147xx12xx100)/(0.2xx44) = 20.04%` <br/> `%H = (w_(2)xx2xx100)/(wxx18) = (0.12xx2xx100)/(0.2xx18) = 6.66%` <br/> `%N = (v_(2)xx25 xx100)/(wxx22400) = (0.74.6)/(8xx0.2) = 46.63%` <br/> Weight percentage of oxygen is obtained <a href="https://interviewquestions.tuteehub.com/tag/indirectly-7311994" style="font-weight:bold;" target="_blank" title="Click to know more about INDIRECTLY">INDIRECTLY</a> <br/> `%O = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> = (%C+%H+%N) = 100-73.33 = 26.67%`</body></html>