0.2m aqueous solution of KCl freezes at -0.68^(@)C calculate van't Hoff factor. K _(f) for water is 1.86 K kg mol ^(-1).

0.2m aqueous solution of KCl freezes at -0.68^(@)C calculate van't Hof

1.	0.2m aqueous solution of KCl freezes at -0.68^(@)C calculate van't Hoff factor. K _(f) for water is 1.86 K kg mol ^(-1).
Answer» <html><body><p></p>Solution :`I = ("Observed propoerty")/("Theoretical <a href="https://interviewquestions.tuteehub.com/tag/property-1170155" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTY">PROPERTY</a> (<a href="https://interviewquestions.tuteehub.com/tag/calculated-907694" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATED">CALCULATED</a>)")` <br/> Given `Delta T_(f) = 0.680 Km ,m=0.2 m, Delta T_(f) ` (observed) `=0.680K,` <br/> `Delta T _(f)` (colculated) `=K _(f). M = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>. 86 K kg mol ^(-1) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.2 mol kg ^(-1) = 0.372K` <br/> `i = ((Delta T _(f)) "observed")/((Delta T _(f))"calculated") = (0.680K )/(0.372K) =1.82`</body></html>