1.

0.2m aqueous solution of KCl freezes at -0.68^(@)C calculate van't Hoff factor. K _(f) for water is 1.86 K kg mol ^(-1).

Answer»

Solution :`I = ("Observed propoerty")/("Theoretical PROPERTY (CALCULATED)")`
Given `Delta T_(f) = 0.680 Km ,m=0.2 m, Delta T_(f) ` (observed) `=0.680K,`
`Delta T _(f)` (colculated) `=K _(f). M = 1. 86 K kg mol ^(-1) XX 0.2 mol kg ^(-1) = 0.372K`
`i = ((Delta T _(f)) "observed")/((Delta T _(f))"calculated") = (0.680K )/(0.372K) =1.82`


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