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0.2m aqueous solution of KCl freezes at -0.68^(@)C calculate van't Hoff factor. K _(f) for water is 1.86 K kg mol ^(-1). |
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Answer» Solution :`I = ("Observed propoerty")/("Theoretical PROPERTY (CALCULATED)")` Given `Delta T_(f) = 0.680 Km ,m=0.2 m, Delta T_(f) ` (observed) `=0.680K,` `Delta T _(f)` (colculated) `=K _(f). M = 1. 86 K kg mol ^(-1) XX 0.2 mol kg ^(-1) = 0.372K` `i = ((Delta T _(f)) "observed")/((Delta T _(f))"calculated") = (0.680K )/(0.372K) =1.82` |
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