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`0.3 g` of an oxalate salts was dissolved in `100 mL` solution. The solution required `90 mL` of `N//20 KMnO_(4)` for complete oxidation. The `%` of oxalate ion in salt is:A. `3.3%`B. `66%`C. `70%`D. `40%` |
Answer» Correct Answer - B Meq. Of `KMnO_(4)=M` eq. of `C_(2)O_(4)^(-2)` `90xx(1)/(2)=100xxN_(C_(2)O_(4)^(2-))` Mmole of oxalate `=(9)/(2xx2)=(9)/(4)` Weight of oxalate `=(9)/(4)xx88xx10^(-3)=22xx9xx10^(-3)` `198xx10^(-3)` `%C_(2)O_(4)^(-2)=(.198)/(.300)xx100=66%` |
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