0.30 g of an organic compound containing C, H and O on combustion yields 0.44 g CO_(2) and 0.18 g H_(2)O. If one mole of compound weighs 60, then molecular formulaof the compound is

0.30 g of an organic compound containing C, H and O on combustion yiel

1.	0.30 g of an organic compound containing C, H and O on combustion yields 0.44 g CO_(2) and 0.18 g H_(2)O. If one mole of compound weighs 60, then molecular formulaof the compound is
Answer» `C_(3)H_(8)O` `C_(2)H_(4)O_(2)` `CH_(2)O` `C_(4)H_(6)O` Solution :`%C = (12)/(44) XX (0.44)/(0.30) xx 100 = 40` `%H = (2)/(18) xx (0.8)/(0.30) xx 100 = 6.66` `%O = 100 - (40.0 + 6.66) = 53.34` Now `C:H:O = (40)/(12) : (6.66)/(1.0) : (53.34)/(16)` = 3.33: 6.66 : 3.33 `:. E.F. = CH_(2)O` E.F. wt. = 12+2+16 = 30 But Mol. wt. = 60 `:. M.F. = CH_(2)O xx (60)/(30) = C_(2)H_(4)O_(2)`