0.316 g of an organic compound, after heating with fuming nitric acid and barium nitrate crystals in a sealed tube gave 0.466 g of the precipitate of barium sulphate. Determine the percentage of sulphur in the compound. (Atomic masses : Ba = 137, S = 32, O = 16, C = 12, H = 1).

0.316 g of an organic compound, after heating with fuming nitric acid

1.	0.316 g of an organic compound, after heating with fuming nitric acid and barium nitrate crystals in a sealed tube gave 0.466 g of the precipitate of barium sulphate. Determine the percentage of sulphur in the compound. (Atomic masses : Ba = 137, S = 32, O = 16, C = 12, H = 1).
Answer» Solution :MASS of the substance taken = 0.316 g Mass of `BaSO_(4)` FORMED = 0.466 g Molecular mass of `BaSO_(4) = 137 + 32 + 64 = 233` Then, mass of S in 0.466 g of `BaSO_(4)` `=(0.466xx32)/(233)g` Percentage of S in compound `=(0.466xx32xx100)/(233xx0.316)` = 20.25