0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed MgNH_(4)PO_(4) which upon heating gave 0.1697 g Mg_(2)P_(2)O_(7). Calculate the percentage of phosphorus in the compound.

0.3160 g of an organic substance was heated with fuming nitric acid in

1.	0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed MgNH_(4)PO_(4) which upon heating gave 0.1697 g Mg_(2)P_(2)O_(7). Calculate the percentage of phosphorus in the compound.
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p>Solution :Percentage of <a href="https://interviewquestions.tuteehub.com/tag/phosphorus-1153299" style="font-weight:bold;" target="_blank" title="Click to know more about PHOSPHORUS">PHOSPHORUS</a> `=62/222xx("Mass of "Mg_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)P_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>))/("Mass of compound")xx100=62/222xx0.1697/0.3160xx100=15 %`</body></html>