0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed `MgNH_(4)PO_(4)` which upon heating gave `0.1697 g Mg_(2)P_(2)O_(7)`. Calculate the percentage of phosphorus in the compound.

0.3160 g of an organic substance was heated with fuming nitric acid in

1.	0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed `MgNH_(4)PO_(4)` which upon heating gave `0.1697 g Mg_(2)P_(2)O_(7)`. Calculate the percentage of phosphorus in the compound.
Answer» Correct Answer - `15` Percentage of phosphorus `=62/222xx("Mass of "Mg_(2)P_(2)O_(7))/("Mass of compound")xx100=62/222xx0.1697/0.3160xx100=15 %`

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0.3160 g of an organic substance was heated with fuming nitric acid in a carius tube to convert phosphorus present into phosphoric acid. Addition of magnesia mixture formed `MgNH_(4)PO_(4)` which upon heating gave `0.1697 g Mg_(2)P_(2)O_(7)`. Calculate the percentage of phosphorus in the compound.

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