0.32 g of an organic compound. after heating with fuming nitric acid

1.	0.32 g of an organic compound. after heating with fuming nitric acid and barium nitrate crystals is a scaled tube gave 0.466 g of barium sulphate. Determine the percentage of sulphur in the compound.
Answer» Weight of organic compound = 0.32 g Weight of BaSO₄ formed = 0.466 g 233 g of BaSO₄ contains = 32 g of sulphate 0.466 g of BaSO₄ contain = \(\frac{32}{233}\) x \(\frac{0.466}{2.32}\) x 100 = \(\frac{32}{233}\) x \(\frac{46.6}{0.32}\) = 19.999 g of sulphur % of sulphur = 20 %

0.32 g of an organic compound. after heating with fuming nitric acid and barium nitrate crystals is a scaled tube gave 0.466 g of barium sulphate. Determine the percentage of sulphur in the compound.

Answer»

Weight of organic compound = 0.32 g

Weight of BaSO₄ formed = 0.466 g

233 g of BaSO₄ contains = 32 g of sulphate

0.466 g of BaSO₄ contain = \(\frac{32}{233}\) x \(\frac{0.466}{2.32}\) x 100

= \(\frac{32}{233}\) x \(\frac{46.6}{0.32}\) = 19.999 g of sulphur

% of sulphur = 20 %