0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal.

0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at N

1.	0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal.
Answer» <html><body><p></p>Solution :Mass of the metal taken (`w_(1)) = 0.65` g Mass of 224 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> of hydrogen <a href="https://interviewquestions.tuteehub.com/tag/liberated-2789268" style="font-weight:bold;" target="_blank" title="Click to know more about LIBERATED">LIBERATED</a> <br/> `w_(2) = 2/(22400) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 224 = 0.02 g` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, Equivalent weight of the metal <br/> `=w_(1)/w_(2) =0.65/0.02 = 32.5`</body></html>