1.

0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metalA. 58B. 32C. 11.2D. 24

Answer» Correct Answer - B
Equivalent weight `=("Mass of metal "xx11200)/("Volume in mL of hydrogen")`
Given, mass of metal `=0.32 g`
volume of hydrogen at `NTP=112 mL`
Equivalent weight `=(0.32xx11200)/112=32`


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