1.

0.32g of metal gave on treatment with an acid 112 mL of hydrogen at STP. Calculate the equivalent weight of the metal

Answer»

58
32
11.2
24

Solution :EQUIVALENT WEIGHT `=("Mass of METAL" xx 11200)/("Volume in mL of HYDROGEN")`
Given, mass of metal `= 0.32g`
volume of hydrogen at NTP `= 112` mL
Equivalent weight`=(0.32xx11200)/(112)=32`


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