0.33g of an organic compound containing phosphorous gave 0.397 g of Mg_(2)P_(2)0_(7) by the analysis. Calculate the percentage of P in the compound.

0.33g of an organic compound containing phosphorous gave 0.397 g of Mg

1.	0.33g of an organic compound containing phosphorous gave 0.397 g of Mg_(2)P_(2)0_(7) by the analysis. Calculate the percentage of P in the compound.
Answer» SOLUTION :WEIGHT of organic compound = 0.33g , Weight of `Mg_(2)P_(2)0_(7)`= 0.397g 222 g of `Mg_(2)P_(2)0_(7)` contains 62 g of phosphorous. `:. 0.397 "g of" Mg_(2)P_(2)0_(7) "will contain" (62)/(222) xx 0.397 "g of P"`. `0.33 "g of organic compound contains" (62)/(222) xx 0.397 "g of P"` `:. 100 "g of organic compound will contain" (62)/(222) xx (0.397)/(0.33) xx 100=(2,461.4)/(73.26)=33.59%` Percentage of phosphorous=33.59%