0.33g of an organic compound containing phosphorous gave 0.397 g of Mg_(2)P_(2)0_(7) by the analysis. Calculate the percentage of P in the compound.

0.33g of an organic compound containing phosphorous gave 0.397 g of Mg

1.	0.33g of an organic compound containing phosphorous gave 0.397 g of Mg_(2)P_(2)0_(7) by the analysis. Calculate the percentage of P in the compound.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of organic compound = 0.33g , Weight of `Mg_(2)P_(2)0_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)`= 0.397g <br/> 222 g of `Mg_(2)P_(2)0_(7)` contains 62 g of phosphorous. <br/>`:. 0.397 "g of" Mg_(2)P_(2)0_(7) "will contain" (62)/(222) xx 0.397 "g of P"`. <br/> `0.33 "g of organic compound contains" (62)/(222) xx 0.397 "g of P"` <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> "g of organic compound will contain" (62)/(222) xx (0.397)/(0.33) xx 100=(2,461.4)/(73.26)=33.59%` <br/> Percentage of phosphorous=33.59%</body></html>