0.35 g of a metal was dissolved in 50 mL N-acid. The whole solution then required 20.85 mL of normal alkaline solution to neutralise the excess of the acid. Calculate the equivalent mass of the metal.

0.35 g of a metal was dissolved in 50 mL N-acid. The whole solution th

1.	0.35 g of a metal was dissolved in 50 mL N-acid. The whole solution then required 20.85 mL of normal alkaline solution to neutralise the excess of the acid. Calculate the equivalent mass of the metal.
Answer» SOLUTION :N//A