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0.35 g of an organic acid was kjeldahlised and the ammonia obtained was passed into 100 cm^(3) of N//5H_(2)SO_(4). The excess of the acid required 154 cm^(3) of N//10 NaOH for neutralisation. Calculate the percentage of nitrogen in the compound. |
Answer» <html><body><p><br/></p>Solution :Volume of unused <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>. <br/> `ubrace(N_(1)V_(1))_("Acid") <a href="https://interviewquestions.tuteehub.com/tag/equiv-2618698" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIV">EQUIV</a> ubrace(N_(2)V_(2))_("Base")` <br/> `1/5xxV=1/10xx154` or `V=77 cm^(3)`. <br/> Step II. <a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a> of <a href="https://interviewquestions.tuteehub.com/tag/nitrogen-1118291" style="font-weight:bold;" target="_blank" title="Click to know more about NITROGEN">NITROGEN</a>. <br/> Volume of acid used `=100-77=23 cm^(3)` <br/> Percentage of `<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=(1.4xx"Normality of acid used"xx"Volume of acid used")/("Mass of compound")=(1.4xx0.2xx23)/035=18.4 %`</body></html> | |