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0.35 g of an organic substance was Kjeldahlised and the ammonia obtained was passed into 100 ml of N/5 H_(2)SO_(4). The excess acid required 154 ml of N/10 NaOH for neutralisation. Calculate the percentage of nitrogen in the compound.

Answer» <html><body><p></p>Solution :Volume of `N//<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> H_(2)SO_(4)` solution taken = 100 mL <br/> The volume of `N//5 H_(2)SO_(4)` neutralised by N/10 <br/> <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> can be obtained as follows : <br/> `N_("acid")xxV_("acid")=N_("<a href="https://interviewquestions.tuteehub.com/tag/alkali-853286" style="font-weight:bold;" target="_blank" title="Click to know more about ALKALI">ALKALI</a>")xxV_("alkali")` <br/> `(N)/(5)xx V_("acid")=(N)/(10)xx154mL` <br/> `V_("acid")=(154)/(10)xxmL` <br/> = 77 <a href="https://interviewquestions.tuteehub.com/tag/nl-571159" style="font-weight:bold;" target="_blank" title="Click to know more about NL">NL</a>. <br/> Therefore, <br/> Volume of `N//% H_(2)SO_(4)` used for <br/> neutralisting ammonia `=(100-77)mL` <br/> `=23mL` <br/> Then, <br/> `"Percentage of nitrogen in the sample "="1.4"xx"Normality volume of acid"` <br/> `("used for neutralising "NH_(3))/("Mass of the compound taken")` <br/> Percentage of nitrogen in the sample <br/> `=(1.4xx1//5xx23)/(0.35)=18.4`</body></html>


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