0.37 gm of alcohol when treated with CH_3MgI liberates 112 ml of CH_4 at STP. The molecularformula of alcohol is

0.37 gm of alcohol when treated with CH_3MgI liberates 112 ml of CH_4

1.	0.37 gm of alcohol when treated with CH_3MgI liberates 112 ml of CH_4 at STP. The molecularformula of alcohol is
Answer» <html><body><p>`C_4H_9OH`<br/>`C_5H_(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>`<br/>`C_3H_7OH`<br/>`C_2H_5OH` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Molecilar <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a></body></html>