0.376g of aluminium reacted with an acid to displace 0·468 litre of hydrogen at NTP. Find the equivalent volume of hydrogen if the equivalent weight of Al is 9.

0.376g of aluminium reacted with an acid to displace 0·468 litre of h

1.	0.376g of aluminium reacted with an acid to displace 0·468 litre of hydrogen at NTP. Find the equivalent volume of hydrogen if the equivalent weight of Al is 9.
Answer» Solution :EQUIVALENT of Al = equivalent of HYDROGEN. `therefore ("weight of Al")/("EQ. weight of Al")=("volume of hydrogen at NTP")/("equivalent volume of hydrogen")` `(0.376)/(9) = (0.468)/("V(litre)")` `therefore"" V=11.2` LITRES.