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0.376g of aluminium reacted with an acid to displace 0·468 litre of hydrogen at NTP. Find the equivalent volume of hydrogen if the equivalent weight of Al is 9. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> of Al = equivalent of <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a>. <br/> `therefore ("weight of Al")/("<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. weight of Al")=("volume of hydrogen at NTP")/("equivalent volume of hydrogen")` <br/> `(0.376)/(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>) = (0.468)/("V(litre)")` <br/> `therefore"" V=11.2` <a href="https://interviewquestions.tuteehub.com/tag/litres-1075876" style="font-weight:bold;" target="_blank" title="Click to know more about LITRES">LITRES</a>.</body></html> | |