0.378 g od an organic compound containing carbon and hydrogen was subjected to cobustion by Liebig's method , the CO_(2) and H_(2)Oformed were passed through potash bulbs and CaCl_(2) (anhydrous) tube. At end of the experiment, the increase in the respective weights were 0.264 g and 0.162 g. Calculate the percentage of carbon and hydrogen.

0.378 g od an organic compound containing carbon and hydrogen was subj

1.	0.378 g od an organic compound containing carbon and hydrogen was subjected to cobustion by Liebig's method , the CO_(2) and H_(2)Oformed were passed through potash bulbs and CaCl_(2) (anhydrous) tube. At end of the experiment, the increase in the respective weights were 0.264 g and 0.162 g. Calculate the percentage of carbon and hydrogen.
Answer» <html><body><p><br/></p>Solution :Increase in weight of <a href="https://interviewquestions.tuteehub.com/tag/potash-1161117" style="font-weight:bold;" target="_blank" title="Click to know more about POTASH">POTASH</a> <a href="https://interviewquestions.tuteehub.com/tag/bulbs-905371" style="font-weight:bold;" target="_blank" title="Click to know more about BULBS">BULBS</a> (mass pf `CO_(2)` evolved) `=0.264 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>` <br/> Increase in weight of `CaCl_(2)` tube (mass of `H_(2)O` forward) `=0.162 g` <br/> `%` of `C=12/44xx("Mass of "CO_(2))/("Mass of compound")xx100=12/44xx0.264/0.378xx100= 19.05%` <br/> `%` of `H=12/18xx("Mass of "H_(2)O)/("Mass of compound")xx100=2/18xx0.162/0.378xx100= 4.76 %`</body></html>