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0.3780 g of an organic chloro compound gave 0.5740 g silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.

Answer» <html><body><p></p>Solution :Here, the <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the substance taken = 0.3780 g <br/> Mass of <a href="https://interviewquestions.tuteehub.com/tag/agcl-368919" style="font-weight:bold;" target="_blank" title="Click to know more about AGCL">AGCL</a> <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a> = 0.5740 g <br/>Now <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> of `AgCl -= 1` g atom of Cl or (108 + 35.5) = 143.5 g of `AgCl -= 35.5 g` of Cl <br/> Applying the relation, Percentage of chlorine `= (35.5)/(143.5) xx ("Mass of AgCl formed")/("Mass of substance taken") xx 100` <br/> `= (35.5)/(143.5) xx (0.5740)/(0.3780) xx 100 = 37.566%`.</body></html>


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