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0.3780 g of an organic chloro compound gave 0.5740 g silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound. |
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Answer» Solution :Here, the MASS of the substance taken = 0.3780 g Mass of AGCL FORMED = 0.5740 g Now 1 MOLE of `AgCl -= 1` g atom of Cl or (108 + 35.5) = 143.5 g of `AgCl -= 35.5 g` of Cl Applying the relation, Percentage of chlorine `= (35.5)/(143.5) xx ("Mass of AgCl formed")/("Mass of substance taken") xx 100` `= (35.5)/(143.5) xx (0.5740)/(0.3780) xx 100 = 37.566%`. |
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