0.4 mole of orthophosphoric acid and 1.0 mole of calcium hydroxide were allowed to react. Calculate the maximum number of moles of calcium phosphate formed.

0.4 mole of orthophosphoric acid and 1.0 mole of calcium hydroxide wer

1.	0.4 mole of orthophosphoric acid and 1.0 mole of calcium hydroxide were allowed to react. Calculate the maximum number of moles of calcium phosphate formed.
Answer» Solution :The stoichiometric equation of `3Ca(OH)_(2)+2H_(3)PO_(4) to Ca_(3)(PO_(4))_(2)+3H_(2)O` 3 MOLES of `CA(OH)_(2)="2 moles of "H_(3)PO_(4)` 1 mole of `Ca(OH)_(2)="0.67 mole of "H_(3)PO_(4)` 0.6 mole of `Ca(OH)_(2)="0.4 mole of "H_(3)PO_(4)` `H_(3)PO_(4)` is the limiting regent. Hence, salt formed is dependent on the availability of acid only. 2 moles of `H_(3)PO_(4)="1 mole of "Ca_(3)(PO_(4))_(2)` 0.4 moles of `H_(3)PO_(4)=?` Number of moles of calcium phosphate formed `=0.4 xx 1/2=0.2"mole"`