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0.40 g of an organic compound gave 0.30 g of silver bromide by carius method. Determine the percentage bromine in the compound. |
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Answer» Mass of the compound `=0.40 g` Mass of silver bromide `=0.30 g` `{:(AgBr,equiv,Br),((108+80)" part",,"80 parts"),(=188 g,,80 g):}` 188g of silver bromide contain bromine `= 80 g` 0.30 g of silver bromide contain bromine `=80/188xx0.30 g` Percentage of bromine `=("Mass of bromine")/("Mass of compound")xx100=80/188xx0.30/0.40xx100=31.9` |
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