0.44 g of a hydrocarbon on complete combustion with oxygen gave 1.8g water and 0.88 g carbon dioxide. Show that these resutls are in asccordance with the law of conservation of mass.

0.44 g of a hydrocarbon on complete combustion with oxygen gave 1.8g w

1.	0.44 g of a hydrocarbon on complete combustion with oxygen gave 1.8g water and 0.88 g carbon dioxide. Show that these resutls are in asccordance with the law of conservation of mass.
Answer» Solution :A hydrocarbon is a compound which consists of carbon and hydrogen only. It UNDERGOES combustion FORMING carbon dioxide and water as products. Formula of Carbon dioxide=`CO_(2)`, Molecular MASS `=12+32=44g`. Formula of water `=H_(2)O`. Molecular mass =2+16=18g Mass of carbon in 0.88 g of `CO_(2)=(12)/(44)xx0.88=0.24g` Mass of hydrogen in 1.8 g of `H_(2)O=(12)/(44)xx1.8=0.20g` Mass of hydrogen in 1.8g of `H_(2)O=(2)/(18)=0.20g` TOTAL masses of carbon and hydrogen in the products `=0.24+0.20=0.44g` This is equal to the mass of hydrocarbon before combustion. Thus, the results are in accordance with the LAW of conservation of mass.