InterviewSolution
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InterviewSolution
| 1. |
0.44g of a monohydric alcohol when added to `CH_(3)MgI` in ether librates at STP, 112`cm^(3)` of methane. With PCC the same alcohol forms a carbonyl compound that answer silver mirror test. The monohydric alcohol is `:`A. `CH_(3)-underset(OH)underset(|)(C)H-CH_(2)-CH_(3)`B. `(CH_(3))_(3)C-CH_(2)OH`C. `CH_(30-underset(OH)underset(|)(C )H-CH_(2)CH_(2)CH_(3)`D. `(CH_(3))_(2)CH-CH_(3)OH` |
| Answer» Correct Answer - B | |