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`0.45 g` of acid (mol. Wt.`=90`) was exactly neutralized by `20 ml` of `0.5(M) NaOH`. The basicity of the given acid isA. `1`B. `2`C. `3`D. `4` |
Answer» Correct Answer - B milli equations of acid `=` milli equation of base `(0.45)/(90)xxbasicity=20xx0.5xx10^(-3)` `basicity=(90xx20xx0.5xx10^(-3))/(0.45)` `=2000xx10^(-3)=2` |
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