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`0.45 g` of an orgainc compound containing only `C, H` and `N` on combustion gave `1.1 g` of `CO_(2)` and `0.3 g` of `H_(2) O`. What is the percentage of `C, H` and `N` in the orgainc compound. |
Answer» Correct Answer - B::C::D `% of C = (12)/(44) xx ("Weight of" CO_(2) xx 100)/("Weight of compound")` `(12 xx 1.1 xx 100)/(44 xx 0.45) = 66.66%` `% of H = (2)/(18) xx ("Weight of" H_(2) O xx 100)/("Weight of compound")` `= (2 xx 0.3 xx 100)/(18 xx 0.45) = 7.4%` `% of N = [100 - (66.66 + 7.4)] = 25.93%` |
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