0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of solute present in 1 lit of this solution is

0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of

1.	0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of solute present in 1 lit of this solution is
Answer» <html><body><p>0.5 gm<br/>25 gm<br/>20 gm <br/>5 g</p>Solution :`(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))=<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` <br/> `N=(0.45xx2+0.6xx1)/(3)=0.5N` <br/> implies 0.5 <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> in 1 lit. = <a href="https://interviewquestions.tuteehub.com/tag/20g-293021" style="font-weight:bold;" target="_blank" title="Click to know more about 20G">20G</a></body></html>