0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of solute present in 1 lit of this solution is

0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of

1.	0.45 N & 0.6 N NaOH solution are mixed in 2:1 by volume. The amount of solute present in 1 lit of this solution is
Answer» 0.5 gm 25 gm 20 gm 5 g Solution :`(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))=N` `N=(0.45xx2+0.6xx1)/(3)=0.5N` implies 0.5 MOLES in 1 lit. = 20G